Question

find the area of a rhombus whose one side measures 5 cm and one diagonal is 8 cm​

Answer 1

Answer:

$15 {cm}^{2}$

Explanation:

Since,

$(side) ^{2} = ( \frac{d1}{2} )^{2} + { (\frac{d2}{2}) }^{2} \\ = > {5}^{2} = ( \frac{8}{2} ) ^{2} + ( { \frac{d2}{2} })^{2} \\ = > 25 = {4}^{2} + ( { \frac{d2}{2} })^{2} \\ = > 25 - 16 =( { \frac{d2}{2} })^{2} \\ = > 9 = ( { \frac{d2}{2} })^{2} \\ = > \sqrt{9 } = \frac{d2}{2} \\ = > 3 = \frac{d2}{2} \\ = > 6 = d2$

$area \: of \: rhombus \: = \frac{1}{2} \times d1 \times d2 \\ = \frac{1}{2} \times 5 \times 6 \\ = 15 {cm}^{2}$

Answer 2

Answer:

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