Question

Find the area of a rhombus whose side is 12cm and its altitude 8cm if one of the diagnal is 16 cm long find the length of other diagnal​

Answer 1

$\underline\mathfrak{Answer}$

96,12

$\underline\mathfrak{Explanation}$

Side of Rhombus = 12 cm

Altitude = 8 cm

$Area \: = base \: \times height$

$= (8 \times 12)cm$

$= 96 {cm}^{2}$

_________________________________________

One diagonal = 16 cm

Other diagonal = ?

$Area = \frac{d1 \times d2}{2}$

Note: d1 and d2 are diagonal 1 and 2 respectively.

$=\frac{16 \times x}{2} = 96 {cm}^{2}$

$= 8x = 96 {cm}^{2}$

$= x = 96 \div 8$

$= x = 12$

Therefore, length of other diagonal is 12 cm

Answer 2

Answer:

ANSWER

Area of rhombus = Base × Height =

2

1

×Product of diagonals

⇒5×4.8=

2

1

×(8×x)

⇒24=

2

1

×(8×x)

⇒x=6 cm