Find the area of a rhombus whose side is 5cm and whose altitude is 4.8cm. If one of its diagonals is 8cm long, find the length of the other diagonal.
Pls give me the answer
Answers
Step-by-step explanation:
area of rhombus= base×altitude
=5×4.8
=24cm²
area of rhombus = 1/2 × product of diagonals
24 =1/2 × 8× other diagonal
24×2/8 = other diagonal
other diagonal= 6cm
Answer:
Answer:
Given:-
The area of rhombus, side is 5cm and altitude is 4.8cm and one of its diagonal is 8cms.
Given:-
The area of rhombus, side is 5cm and altitude is 4.8cm and one of its diagonal is 8cms.
To Find:-
Find the length of other diagonal. ....?
Solutions:-
Let the length of the other diagonal of the rhombus be x.
A rhombus is a special are of a parallelogram.
The area of a parallelogram is the product of its base and height.
Area of the Rhombus = base × height
= 5cm × 4.8cm
= 24cm²
Area of rhombus = 1/2 (products of its diagonal)
⟹ 24cm² = 1/2 × (8cm + x)
⟹ x = 24 × 2 / 8
⟹ x = 48/8
⟹ x = 6cm
Hence, the length of the other diagonal of the Rhombus is 6cm.
Some Important:-
A rhombus all side are equal.
A rhombus opposite angle are equal.
A rhombus the sum of adjacent angle angle supplementary i.e. (<A + <D = 180°).
A rhombus, each diagonal of a rhombus divides it into two congruent triangle.
A rhombus, if one angle is right, then all angle are right.
Diagonal of a rhombus bisect each other and also perpendicular to each other.
More important:-
Area of rhombus = b × h
Perimeter of rhombus = 4 × side
where,
b = base
h = height
p = perimeter
a = area:-