Question

Find the area of a rhombus whose side is 5cm and whose altitude is 4.8cm. If one of its diagonals is 8cm long, find the length of the other diagonal​

Answer 1

Answer:

Given :-

$side = 5cm \\ one \: diagonal = 8cm$

To find :-

$length \: of \: another \: diagonal$

Solution :-

In Rhombus ABCD , AC and BD are diagonals

intersect at point o.

AB= 5cm, OB=4cm, OA= ?

By using Pythagoras theorem

(OA) ²= (AB) ²- (OB) ²

(OA) ²= (5) ²-(4) ²

(OA) ²= √9

(OA) =3

BD= OB+ OD

= 3+3

= 6 cm

:. Length of another diagonal = 6 cm

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Answer 2

Answer:

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