Question

Find the area of a rhombus whose side is 5cm and whose altitude is 4.8cm. If one of its diagonals is 8cm long, find the length of the other diagonal. answer for more points ​

Answer 1

Answer:

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Step-by-step explanation:

Area of rhombus = Base × Height = 1/2

×Product of diagonals

⇒5×4.8= 1/2 ×(8×x)

⇒24= 1/2 ×(8×x)

⇒x=6 cm

Answer 2

Given :-

$side = 5cm \\ one \: diagonal = 8cm$

To find :-

$length \: of \: another \: diagonal$

Solution :-

Solution :-In Rhombus ABCD , AC and BD are diagonals intersect at point o.

intersect at point o. AB= 5cm, OB=4cm, OA= ?

By using Pythagoras theorem (OA) ²= (AB) ²- (OB) ²

(OA) ²= (5) ²-(4) ²

(OA) ²= √9

(OA) =3

BD= OB+ OD

= 3+3

= 6cm

:. Length of another diagonal = 6 cm

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