Question

Find the area of a rhombus whose side is 6 cm and whose altitude is 4cm if one of its diagonals is 8cm long.find the length of the other diagonal

Answer 1

area of rhombus=h×b=6×4=24cm²
as d1=8
we have to find d2
area of rhombus=(1/2)×d1×d2
24=(1/2)×8×d2
24=4×d2
d2=6
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Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =6×4=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.