find the area of a rhonbus,one side of which measures 20cmand one of whose diagonals is 24cm.
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Area of rhombus = 1/2 p √4a^2 -p^2
where, p is the length of diagonal & a is the length of one side.
Area = (1/2) × 24 √(4×20×20) - (24×24)
= 12 √1024
= 11 × 32
= 352 cm sq.
hope this helped you,
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where, p is the length of diagonal & a is the length of one side.
Area = (1/2) × 24 √(4×20×20) - (24×24)
= 12 √1024
= 11 × 32
= 352 cm sq.
hope this helped you,
plzzz mark as brainliest .. ........................!
Answered by
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Answer:
A = 384cm²
a = Side = 20cm
p = Diagonal = 24 cm
a = pq / 2
a = p² + q² / 2
a = 1 / 2 p √4² - p²
= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³
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