find the area of a right angled triangle abc whose angle b=90 degree angle c=45 degree ac 6 cm
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Answer:
Step-by-step explanation:
∠ a+ ∠ b+ ∠ c=180° [A.S.P.T]
∠ a +90°+45°=180°
∠a+135°=180°
∠ a = 180°-135°
∠ a =45°
as angle a=angle c
AB=BC
So,
AB²+BC²=AC²
x²+x²=6²
2x²=36
x²=36/2
x²=18
x=√18
x=4.24
therefore
area of a triangle= 1/2*base*height
=1/2*4.24*4.24
=8.98 cm²
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