find the quadratic polynomial whose zeroes are
√2+3 and 2 -3
are
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Step-by-step explanation:
Zeroes are a=√2+3 and b=√2-3.
Sum of zeroes, (a+b)=√2+3+√2 -3=2√2.
Product of zeroes, ab
=>(√2+3)(√2-3)=(√2)²-3²=2-9=-7.
Equation:
x²-(a+b)x+ab.
The reqrired equation is:
x²-2√2x-7=0.
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