Find the area of a right angled triangle, if the radius of it's circumcircle is 7.5 cm and it's altitude drawn to the hypotenuse is 6 cm long.
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Let ∆ABC be right-angled triangle at B.
Hypotenuse AC = Diameter of it's circumcircle.
Hypotenuse AC = (2×7.5) cm = 15 cm.
Let BD perpendicular AC. Then , BD = 6 cm.
Therefore,
Ar(∆ABC) = (1/2 × AC × BD)
Ar(∆ABC) = 1/2 × 15 × 6 = 45 cm².
Hypotenuse AC = Diameter of it's circumcircle.
Hypotenuse AC = (2×7.5) cm = 15 cm.
Let BD perpendicular AC. Then , BD = 6 cm.
Therefore,
Ar(∆ABC) = (1/2 × AC × BD)
Ar(∆ABC) = 1/2 × 15 × 6 = 45 cm².
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1
Answer:
45 cm²
Step-by-step explanation:
Let triangle ABC Be right-angled at B
Hypotenuse AC
=diameter of its circumcircle
=(2×7.5) cm = 15 cm
Let BDperpendicular AC. Then , BD = 6 cm.
therefore ar(triangle ABC) =[½AC×BD] =[½×15×6] CM²= 45
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