find the area of a right triangle whose base is 1.2 metre and hypotenuse is 3.7 m
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Answered by
21
Base = 1.2 m
Hypotenuse = 3.7 m

Perpendicular = 3.5 m
Area = Base *Perpendicular /2
= 1.2 * 3.5 /2
= 0.6 * 3.5
= 2.1 m^2
Hypotenuse = 3.7 m
Perpendicular = 3.5 m
Area = Base *Perpendicular /2
= 1.2 * 3.5 /2
= 0.6 * 3.5
= 2.1 m^2
Shubhamshivam:
thanks frend
Answered by
8
hey...
to find area of right triangle we need BASE and HEIGHT.
Height can be find out by using pythagores theorem.
area = 2.1 m^2.
to find area of right triangle we need BASE and HEIGHT.
Height can be find out by using pythagores theorem.
area = 2.1 m^2.
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