Question

Find the area of a right triangle whose base is 1.2m and hypotenuse is 3.7m
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Answer 1

Answer:

Step-by-step explanation:

Given:

base = 1.2 m

hypotenuse = 3.7 m

By Pythagoras theorem,

${h}^{2} = \: {b}^{2} + \: {p }^{2} \\ {p }^{2} = \: {h}^{2} - \: {b}^{2}$

${p}^{2} = \: {3.7}^{2} - {1.2}^{2} \\ { p}^{2} = 13.69 - 1.44 \\ {p }^{2} = 12.25 \\ p = \sqrt{12.25 } \\ p = 3.5 \: m$

Therefore ,

$area \: = \frac{1}{2} \times base \times height \\ area \: = \frac{1}{2} \times 1.2 \times 3.5 \\ area = 0.6 \times 3.5\\ area = 2.1 {m}^{2}$

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Answer 2

Answer:

the are of triangle is 2.1 cm

Step-by-step explanation:

According to Pythagoras theorem,

(AB)^2 + (BC) ^2 = (BA) .... Here BA is hypotenuse

we have to find the side AB,

(AB) ^2 = (AC) ^2 - (BC) ^2

= (3.7)^2 - (1.2) ^2

= 13.69 - 1.44

= 12. 25

AB = 3.5 CM

therefore, side AB = 3.5 CM.

then, area of triangle = 1/2 x base x height

= 1/2 x 1.2 x 3.5

= 1/2 x 4.2

= 2.1 CM^2