Question

Find the area of a right triangle whose hypotenuse is 13cm and one side is 5cm

Answer 1

Hsq. =Ssq+Ssq
13sq=5sq+Ssq
169=25+Ssq
169-25=Ssq
144=Ssq
S=12

Answer 2

Answer:

Area=$30cm^{2}$

Step-by-step explanation:

Given:

Hypotenuse = 13cm

Base = xcm(It is not given)

Height = 5cm

Using RHS:

$AB^{2}=AC^{2}+BC^{2}$

$13^{2}=5^{2}+x^{2}$

$169=25+x^{2}$

$169-25=x^{2}$

$144=x^{2}$

$\sqrt{144}=x$

∴$x=12$

To find Area:

Area=$\frac{1}{2}$×b×h

Area=$\frac{1}{2}$×12×5

Area=$30cm^{2}$