Math, asked by thakur123warrior, 3 months ago


Find the area of a right triangle whose hypotenuse
is 17 cm and one of the sides which forms a night
angle is 8 cm


thakur123warrior: thanks

Answers

Answered by mdatif146
1

Answer:

Here's ur answer

Step-by-step explanation:

Let the other side be x

By Pythagoras theorem:-

(17)² = (8)²+x²

⇒x ²=225

⇒x=15

Area = ½ (base) (height)

½ (15)(8)=60cm

Final answer = 60cm

Hope it's helpful.. if so mark me as brainliest

Answered by ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ
17

 \huge { \orange{ᴀɴ ᴡᴇʀ}}

ʟᴇᴛ ᴛʜᴇ ᴏᴛʜᴇʀ sɪᴅᴇ ʙᴇ x

 { \red{ʙʏ \:  ᴘʏᴛʜᴀɢᴏʀᴀs \:  ᴛʜᴇᴏʀᴇᴍ :-}}

(17)² = (8)² + x²

➝ x² = 225

➝ x = 15

ᴀʀᴇᴀ ➝ ½ × base × height

➝ ½ × 15 × 8

=> 60 cm²

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