Question

Find the area of a sector of a circle with radius 9 cm if the angle of the sector is 60.

Answer 1

$r \: = 9 \\ \alpha = 60 \\ area \: = \pi \times {r}^{2} \times \frac{ \alpha }{360} \\ = \frac{22}{7} \times {9}^{2} \times \frac{60}{360} \\ = 42.428 {cm}^{2}$