Question

find the area of a sector with a central angle of 30° and a radius of 9cm.​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given:-

• Angle of the sector as 30 degree
• Radius as 9 cm

To find:-

Area of the sector

Let's Do!

We know that area of the sector is:-

$\bf{\dfrac{\theta}{360}\times \pi \times r^2}$

So, here, we have theta as 30.

We have radius as 9.

We can place it as:-

$\rm{\dfrac{30}{360}\times \dfrac{22}{7}\times 9}$

$=\dfrac{3}{4}\pi$ is the required answer in terms of pi.

And, 2.45 cm^2 is the approximate answer.

Remember:-

Area of the sector is equal to:-

$\sf{\dfrac{\theta}{360}\times \pi \times r^2}$

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

Find the area of a sector with a central angle of 30° and a radius of 9cm.

$\huge{\boxed{\rm{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Central angle of sector = 30°
• Radius of sector = 9 cm

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Sector's area

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

• Sector's area = 2.45 cm²

${\bigstar}\large{\boxed{\sf{\pink{Full \: solution}}}}$

$\large\purple{\texttt{Compulsory to know –}}$

$\large\green{\texttt{Sector's area formula}}$

$\frac{theta}{360} \times \pi \times {r}^{2}$

• π is pie
• π's value = 22/7

$\large\purple{\texttt{Putting the values as}}$

$\mapsto$ Value of theta = 30

$\mapsto$ Value of radius = 9 cm

$\large\purple{\texttt{Now substituting the value}}$

$\frac{30}{360} \times \frac{22}{7} \times {9}^{2}$

By cancelling the terms we get result -

$\mapsto$ 3/4 π

By dividing 3 by 4 we get below result -

$\mapsto$ 2.45 cm²

$\large{\boxed{\sf{2.45cm² \: is \: Answer}}}$

@Itzbeautyqueen23

Hope it's helpful

Thank you :)