Question

Find the area of a square park whose perimeter is320m​

Answer 1

$\huge \fbox{Answer}$

$\large \underline{ \frak{ \color{blue}Given:}}$

$\mapsto \sf{Perimeter \: of \: square=320m}$

$\large \underline{ \frak{ \color{bl}To \: find:}}$

$\leadsto \sf{Area \: of \: square. }$

$\large \underline{ \frak{ \color{indigo}Formula \: required:}}$

$\dag{ \boxed{ \rm{Side \: of \: square= \frac{Perimeter}{4} }}}$

$\dag{ \boxed{ \rm{Area \: of \: square= {Side}^{2} }}}$

$\large \underline{ \pink{ \frak{According \: to \: Question: }}}$

$\sf{ : : \implies{{Side \: of \: square= \frac{Perimeter}{4} }}}$

$\sf{ : : \implies{{Side \: of \: square= \frac{320}{4} m}}}$

$\sf{ : : \implies{{Side \: of \: square= 80m}}}$

$\bf{Then,}$

${:: \implies{ \sf{Area \: of \: square= {(Side)}^{2} }}}$

${:: \implies{ \sf{Area \: of \: square= {(80m)}^{2} }}}$

${:: \implies{ \sf{Area \: of \: square= 6400m^{2} }}}$

$\bf{Hence, }$

$\: \: \: \: \: \: \: \: \: \: \: \star \underline{ \boxed{ \rm{Area \: of \: square= {Side}^{2} }}}$

Answer 2

$\sf \large \underbrace{ \underline{Understanding \: the \:Concept }}$

Here's the concept of area of square as well as perimeter of square is applied, where we have given the perimeter of square to be 320m and have to find the Area of square. First we have to find the side of Square from formula of perimeter of square then put that value in formula to find area of square.

So let's start!

‎ ‎ ‎ ‎ ‎ ‎

$\underline{\boxed{ \sf★ \: Perimeter \: of \: square=4×side}}$

$\sf \implies320m=4×Side$

$\sf \implies \dfrac{320m}{4}=Side$

$\sf \implies 80m=Side$

Hence the side of Square is 80m.

‎ ‎ ‎ ‎ ‎ ‎

Now we have to find area of square.

$\large \underline{ \boxed{\sf ★ \: Area \: of \: square=Side²}}$

$\sf \implies \: 80m \times 80m$

$\sf \implies \: 6400 {m}^{2}$

Hence the area of square is 6400m².

$\sf \large \underbrace{ \underline{More \: formulae \: to \: know}}$

$\sf★Area \: of \: rectangle=Length×Breadth$

$\sf★Area \: of \: circle=πr²$

$\sf★Area \: of \: triangle=\dfrac{1}{2}×Base×height$

$\sf★Perimeter \: of \: rectangle=2(L+B)$

$\sf★ Perimeter \: of \: circle=2πr$