Question

Find the area of a square, the product of whose diagonals is 66 cm2

Answer 1

side*side:66*66:4,356 answer

Answer 2

Answer:

33 sq.cm.

Step-by-step explanation:

Let the diagonal be x

We know that the length of diagonals of square is congruent

We are given that the product of length of diagonals is 66

So,$x^2=66$

$x=\sqrt{66}$

Length of diagonal = $\sqrt{2}a$

a is the side of square

So, $\frac{\sqrt{66}}{\sqrt{2}}=a$

Area of square = $Side^2 =(\frac{\sqrt{66}}{\sqrt{2}})^2=33 cm^2$

Hence the area of rectangle is 33 sq.cm.