find the area of a square whose diagonal is 7√2 cm long
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Answered by
17
we know
diagonal of square = under root 2 *side.
7root2=side *root2.
side=7.
area of square =side *side
=7*7. =49cm.
plse mark brainliest plse
diagonal of square = under root 2 *side.
7root2=side *root2.
side=7.
area of square =side *side
=7*7. =49cm.
plse mark brainliest plse
deepak160412:
plse mark brainliest
Answered by
7
Hey buddy here is ur answer !!!
Here Triangle ABC = Triangle ACD
Area of triangle ABC = 1/2 × B × H
1/2 × 7 ROOT 2 × 1/2 × 7 ROOT 2
1/2 × (2root)^2 (7)^2 × 1/2
(49×2)/4
49/2
24.5
Similarly ,
In triangle ACD = 24.5
Area of Square = triangle ABC + triangle ACD
24.5 + 24.5
49.0
49 cm
Hope u like my process !!
》》 BE BRAINLY 《《
Here Triangle ABC = Triangle ACD
Area of triangle ABC = 1/2 × B × H
1/2 × 7 ROOT 2 × 1/2 × 7 ROOT 2
1/2 × (2root)^2 (7)^2 × 1/2
(49×2)/4
49/2
24.5
Similarly ,
In triangle ACD = 24.5
Area of Square = triangle ABC + triangle ACD
24.5 + 24.5
49.0
49 cm
Hope u like my process !!
》》 BE BRAINLY 《《
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