Question

Qadrilateral ABCD is a rhombus . Then prove that

( AB )^2 + ( BC )^2 + ( CD )^2 = 2 × CD × AD

#45points

Answer 1

yaha pe shyyad 3×CD×AD aayega

Answer 2

rhombus ABCD, AB = BC = CD = DA We know that diagonals of a rhombus bisect each other perpendicularly. That is AC ⊥ BD, ∠AOB=∠BOC=∠COD=∠AOD=90° and Consider right angled triangle AOB AB^2 = OA^2 + OB^2 [By Pythagoras theorem] ⇒ 4AB^2 = AC^2+ BD^2