find the area of a square whose perimeter is 260 point 8 m
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Answered by
7
hello frnd!
here's ur answer...
given the perimeter of the square is 260.8m
we know that a square has 4 equal sides.
therefore side×4=260.8m
→side=260.8/4
→side=65.2m
hence it's area=side²
=65.2×65.2
=4251.04m²
hope this helps..!
here's ur answer...
given the perimeter of the square is 260.8m
we know that a square has 4 equal sides.
therefore side×4=260.8m
→side=260.8/4
→side=65.2m
hence it's area=side²
=65.2×65.2
=4251.04m²
hope this helps..!
amashi:
mai agli bar kar donga
Answered by
3
perimeter = 260.8
side * 4 = 260.8
side = 260.8/4
side = 65.2
therefore, area = side sq
area = 65.2*65.2
area = 4251.04 sq ans
side * 4 = 260.8
side = 260.8/4
side = 65.2
therefore, area = side sq
area = 65.2*65.2
area = 4251.04 sq ans
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