Math, asked by amashi, 1 year ago

find the area of a square whose perimeter is 260 point 8 m

Answers

Answered by Anonymous
7
hello frnd!

here's ur answer...

given the perimeter of the square is 260.8m

we know that a square has 4 equal sides.

therefore side×4=260.8m

→side=260.8/4

→side=65.2m

hence it's area=side²

=65.2×65.2

=4251.04m²

hope this helps..!

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Answered by dikshita12bharadwaj
3
perimeter = 260.8
side * 4 = 260.8
side = 260.8/4
side = 65.2
therefore, area = side sq
area = 65.2*65.2
area = 4251.04 sq ans
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