Question

find the area of a square whose side length = 7 cm​

Answer 1

Answer:

the formula is side into side =7×7=49

Answer 2

${ \underline{ \underline{ \sf{ \pmb{Appropriate\: Question}}}}}$

Find the area of a square whose side length is 7 cm.

${ \underline{ \underline{ \sf{ \pmb{Solution}}}}}$

We know that,

Area of square = a²

So,

= 7²

= 7 × 7

= 49 cm

${ \underline{ \underline{ \sf{ \pmb{ \blue{Additional \: Information}}}}}} :$

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \small\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}\end{gathered}\end{gathered}$