find the area of a trapezium PQRS.
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The area of a trapeziums is 273 cm
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ar of trapezium = 1/2( sum of parallel side ).height
= 1/2 (13+13+16)h
=21h
now , by pythagores
square of RU = square of RT+square of UT
169=64+square of RT
RT=under root of 105
ar = 21(10.24)
ar= 215.04
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