Find the area of a trapezium whose parallel sides are 25cm and 10cm the distance between them is 15cm
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Answer:Area of a trapezium = 1/2(sum of parallel sides) x (perpendicular diatance between them)
= 1/2(25 + 13) x 8 = 152cm2
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Answer:
area of trapezium = 1/2* sum of parallel sides * Height
=1/2*25+10*15
=525/2 or 262.5 is the answer
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