Question

find the area of a triangle ABC with a b (1 ,- 4 )and midpoint of side through a being( 2 -1 )and (0 - 1)​

Answer 1

Answer:

Step-by-step explanation:

∆ABC has 3 points A,B,C.

coordinates of A are (1,-4)

mid point of AB = (2,-1)

mid point of AC = (0,-1)

we need to find

_______________

let coordinate to B(x1,y1)

mid point of AB is

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»

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so,B(x1,y1) is B(3,2)

_______________

let coordinates of C(x2,y2)

mid point of AC is

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so,C(x2,y2) is C(-1,2)

__________

area of ∆ABC

» ½[x1(y2-y3] + x2(y3-y1) + x3(y1-y2)]

» ½[3(2-{-4})+(-1)(-4-2)+1(2-2)]

» ½[18+6+0]

»½×24

» 12

area of ∆ABC is 12 sq. units.

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