find the area of a triangle having sides 40mm,20mm and 28mm.
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heron's formula
s = a+b+c/2
= 40+20+28/2
=44
area = √s(s-a)(s-b)(s-c)
=√44 (44-40) (44-20) (44-28)
=√44×4×24×16
=√4×11×4×6×2×2×4×4
=4×4×2√6×11
=32√66 mm^2
s = a+b+c/2
= 40+20+28/2
=44
area = √s(s-a)(s-b)(s-c)
=√44 (44-40) (44-20) (44-28)
=√44×4×24×16
=√4×11×4×6×2×2×4×4
=4×4×2√6×11
=32√66 mm^2
Anonymous:
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