Question

Find the area of a triangle if its sides are. (i)52cm , 60cm and 56cm​

Answer 1

Answer: answer is 1344

Step-by-step explanation

Answer:

Answer:Step-by-step explanation:

Answer:Step-by-step explanation:ANSWER :-

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is                                  \begin{gathered}=\frac{(a+b+c)}{2} \\\end{gathered}=2(a+b+c)

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is                                  \begin{gathered}=\frac{(a+b+c)}{2} \\\end{gathered}=2(a+b+c)                                  \begin{gathered}=\frac{(52+60+56)}{2} \\=\frac{168}{2}=84\end{gathered}=2(52+60+56)=2168=84

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is                                  \begin{gathered}=\frac{(a+b+c)}{2} \\\end{gathered}=2(a+b+c)                                  \begin{gathered}=\frac{(52+60+56)}{2} \\=\frac{168}{2}=84\end{gathered}=2(52+60+56)=2168=84By Herons formula,

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is                                  \begin{gathered}=\frac{(a+b+c)}{2} \\\end{gathered}=2(a+b+c)                                  \begin{gathered}=\frac{(52+60+56)}{2} \\=\frac{168}{2}=84\end{gathered}=2(52+60+56)=2168=84By Herons formula,\begin{gathered}\sqrt{ s(s-a)(s-b)(s-c)}\\=\sqrt{84(84-52)(84-60)(84-56)}\\=\sqrt{84×32×24×28} \\=2×3×7×2×2×2×2×2\\=1344\end{gathered}s(s−a)(s−b)(s−c)=84(84−52)(84−60)(84−56)=84×32×24×28=2×3×7×2×2×2×2×2=1344

Answer:Step-by-step explanation:ANSWER :-The sides of the Traingle are ,\begin{gathered}a=52cm,b=60cm,c=56cm\\\end{gathered}a=52cm,b=60cm,c=56cm∴ Semi perimeter of the traingle is                                  \begin{gathered}=\frac{(a+b+c)}{2} \\\end{gathered}=2(a+b+c)                                  \begin{gathered}=\frac{(52+60+56)}{2} \\=\frac{168}{2}=84\end{gathered}=2(52+60+56)=2168=84By Herons formula,\begin{gathered}\sqrt{ s(s-a)(s-b)(s-c)}\\=\sqrt{84(84-52)(84-60)(84-56)}\\=\sqrt{84×32×24×28} \\=2×3×7×2×2×2×2×2\\=1344\end{gathered}s(s−a)(s−b)(s−c)=84(84−52)(84−60)(84−56)=84×32×24×28=2×3×7×2×2×2×2×2=1344∴The area of traingle is 1344 cm² .

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Answer 2

Answer:

Step-by-step explanation:

ANSWER :-

The sides of the Traingle are ,

$a=52cm,b=60cm,c=56cm$

∴ Semi perimeter of the traingle is

                                  $=\frac{(a+b+c)}{2}$

                                  $=\frac{(52+60+56)}{2} \\=\frac{168}{2}=84$

By Herons formula,

$\sqrt{ s(s-a)(s-b)(s-c)}\\=\sqrt{84(84-52)(84-60)(84-56)}\\=\sqrt{84×32×24×28} \\=2×3×7×2×2×2×2×2\\=1344$

∴The area of traingle is 1344 cm² .