find the area of a triangle pqr with the vertices P(-7,-4), Q(5,2),R(4,7)
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Let p(-7, -4) be x1 and y1
Let q(5, 2) be x2 and y2
Let r(4, 7) be x3 and y3
Therefore, area triangle PQR equals to
1/2 * [(-7) * (2-7)+(5)*(7-(-4)+(4)*(-4-2)]
Equal to, 1/2*[(-7)*(-5)+(5)*(7+4)+(4)*(-6)]
Equal to, 1/2*[35+55-24]
Equal to, 1/2*[90-24]
Therefore, 1/2* 66
Therefore, area triangle PQR equals to 33 sq. units
Let q(5, 2) be x2 and y2
Let r(4, 7) be x3 and y3
Therefore, area triangle PQR equals to
1/2 * [(-7) * (2-7)+(5)*(7-(-4)+(4)*(-4-2)]
Equal to, 1/2*[(-7)*(-5)+(5)*(7+4)+(4)*(-6)]
Equal to, 1/2*[35+55-24]
Equal to, 1/2*[90-24]
Therefore, 1/2* 66
Therefore, area triangle PQR equals to 33 sq. units
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