find the area of a triangle two side of which are 18 cm and 10 cm and the perimeter is 42 CM
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Hey!
Side 1 =18cm
Side 2=10cm
Perimeter=42cm
Side 3=? (let it be x)
Perimeter of a triangle= Sum of all the sides
42=18+10+x
42=28+x
42-28=x
x=14cm
Area of the triangle=>
s= s1+s2+s3/2
s=18+10+42
s=42/2
s=21
Area= √ s(s-s1)(s-s2)(s-s3)
√21(21-18)(21-10)(21-14)
√21(3)(11)(7)
√4851
Area= 69.64cm^2
Hope it helps...!!!
Side 1 =18cm
Side 2=10cm
Perimeter=42cm
Side 3=? (let it be x)
Perimeter of a triangle= Sum of all the sides
42=18+10+x
42=28+x
42-28=x
x=14cm
Area of the triangle=>
s= s1+s2+s3/2
s=18+10+42
s=42/2
s=21
Area= √ s(s-s1)(s-s2)(s-s3)
√21(21-18)(21-10)(21-14)
√21(3)(11)(7)
√4851
Area= 69.64cm^2
Hope it helps...!!!
Tuhina222:
whr is the area
oops!
Let me edit!
Done!
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