find the area of a triangle two side of which are 18 cm and 10 cm and the perimeter is 42 cm
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Side A=18
Side B=10
Side C=28-42
Side C=14
s=a+b+c÷2
s=18+10+14÷2
s=42÷2
s=21
Area of Δ =√s(s-a)(s-b)(s-c)
√21(3)(11)(7)
3×7×3×11×7
11√7×3
11√21cm
Side B=10
Side C=28-42
Side C=14
s=a+b+c÷2
s=18+10+14÷2
s=42÷2
s=21
Area of Δ =√s(s-a)(s-b)(s-c)
√21(3)(11)(7)
3×7×3×11×7
11√7×3
11√21cm
sneharai2:
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