Find the area of a triangle, two sides of which are 10 cm and 6 cm and the semi perimeter is 14 cm.
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Perimeter =14*2=28
Sides are 10,6 ,28-10-6 =12
Area = square root of s(S-a)(S-b)(a-c)
= square root of 14*4*8*2 8_|14 square cm
Sides are 10,6 ,28-10-6 =12
Area = square root of s(S-a)(S-b)(a-c)
= square root of 14*4*8*2 8_|14 square cm
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