Question

Find the area of a triangle two sides of which are 18 cm and 12 cm and the
perimeter is 44 cm.

Answer 1

Given

Side 1 = 18 cm

Side 2 = 12 cm

Perimeter = 44 cm

Perimeter = side + side + side

44 cm = 18 cm + 12 cm + side

44 cm - 30 cm = side

side = 14 cm

$semi \: perimeter \: = \frac{a + b + c}{2}$

$semi \: perimeter \: = \frac{18 + 12 + 14}{2}$

$semi \: perimeter \: = 22 \: cm$

Area = √[s(s-a)(s-b)(s-c)]

Area = √[22(22-18)(22-12)(22-14)]

Area = √22 × 4 × 10 × 8

Area = √7040

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