Question

find the area of a triangle , two sides of which are 60 m and 80 m and perimeter 260 m

Answer 1

a+b+c=perimeter
60+80+c=260
140+c=260
c=260-140=120

s=260/2=130
area=√s(s-a)(s-b)(s-c) =√130(130-60)(130-80)(130-120)
=√130(70)(50)(10)
100√13*7*5
100√445