find the area of a triangle ,two sides of which are 8cm and 11cm and the perimeter is 32cm
Answers
Answered by
3
Gujjar ❤️
A=s(s﹣a)(s﹣b)(s﹣c)
P=a+b+c
s=a+b+c
2
Solving forA
A=1
4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1
4·﹣324+4·323·8+4·323·11﹣4·(32·8)2﹣12·322·8·11﹣4·(32·11)2+8·32·82·11+8·32·8·112≈43.8178cm²
Answered by
17
Answer:
8√30 cm²
Step-by-step explanation:
Let,a=11cm
b=8cm
c=?
Perimeter=32cm
⇒a+b+c=32cm
⇒11cm+8cm+c=32cm
⇒19+c=32cm
⇒c=13cm
Now,semi-perimeter(s)=a+b+c/2=11cm+8cm+13cm=32/2=16cm
∴Area of Δle=√s(s-a)(s-b)(s-c)
=√16(16-11)(16-8)(16-13)
=√16×5×8×3
=√8×2×5×8×3
=√(8)²×2×5×3
=8√2×5×3
=8√30 cm²
Please mark it as brainlist answer
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