Question

Find the area of a triangle whose base is 12cm and hypotenuse is 13cm

Answer 1

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$Base \: of \: trianle \: (b) = 12cm \\ Hypotenuse \: of \: triangle \: (h) = 13cm \\ \\ We \: have \: to \: Find \: height (l)\: \\ \\ Now, \: Using \: pythagoras \: theorem : \\ \\ = > (h) { }^{2} = (b) {}^{2} + (l) {}^{2} \\ \\ = > l {}^{2} = 13 {}^{2} - 12 {}^{2} \\ \\ = > l {}^{2} = 169 - 144 \\ \\ = > l {}^{2} = 25 \\ \\ = >l = 5cm \\ \\ So, \: Height \: of \: triangle \: is \: 5cm \\ \\ Area \: of \: triangle \: = \frac{1}{2} \times base \times height \\ \\ = > \frac{1}{2} \times 5 \times 12 \\ \\ = > 30cm {}^{2} \\ \\ So, \: Area \: of \: triangle \: is \: 30cm {}^{2} ...$
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Answer 2

area of triangle is 30cm^2