Question

Find the area of triangular field whose sides 42cm 34cm and 20cm in length also find the height corresponding to the longest side

Answer 1

HLO MATE ✋✋
Simran Here !!!!!

HERE IS UR ANSWER ____________
________________________________⭐⭐⭐

$ABC \: is \: a \: triangular \: field, \: \\ AB (a)\: = 42cm \\ BC(b) = 34cm \\ AC(c) = 20cm \\ \\ First, \: we \: have \: to \: Find \: semiperimeter (s)\: of \: triangular \: field \: \\ s = \frac{a + b + c}{2} \\ s = \frac{42 + 34 + 20}{2} \\ s = \frac{96}{2} \\ = > s = 48cm \\ \\ Using \: heron's \: formula : \\ \\ Area \: of \: triangle \: = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = > \sqrt{48(48 - 42)(48 - 34)(48 - 20)} \\ \\ = > \sqrt{48(6)(14)(28)} \\ \\ = > \sqrt{112896} \\ \\ = > 336cm {}^{2} \\ \\ So ,\: Area \: of \: triangle \: is \: 336cm {}^{2} \\ \\ Now ,\: \\ Area \: of \: triangle \: considering \: the \: longest \: side \: as \: the \: base \: = \frac{1}{2} \times b \times h \\ = > 336 = \frac{1}{2} \times 42 \times h \\ = > \frac{672}{42} = h \\ = > h = 16cm \\ \\ So, \: Height \: of \: triangular \: field \: is \: 16cm..$
_______________________________⭐⭐⭐
HOPE IT HELPS UH ☺
^_^

❤BE BRAINLY❤
Nd Keep Smiling ☺