Question

Find the area of a triangle whose base length is 22cm and the corresponding height is 13 cm​

Answer 1

Answer: Base =22cm

HEIGHT =13 CM

area of triangle =1/2×base ×height

1/2×22×13

11×13

143 cm²

hence it is your answer dear

Step-by-step explanation:

Mark me as brainliest.. :)

Answer 2

Answer:

Given :-

• A triangle whose base length is 22 cm and the corresponding height is 13 cm.

To Find :-

• What is the area of a triangle.

Formula Used :-

$\clubsuit$ Area Of Triangle Formula :

$\small \bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Triangle)} =\: \dfrac{1}{2} \times Base \times Height}}}\: \: \: \bigstar$

Solution :-

Given :

• Base Length = 22 cm
• Height = 13 cm

According to the question by using the formula we get,

$\small \implies \bf Area_{(Triangle)} =\: \dfrac{1}{2} \times Base \times Height$

$\implies \sf Area_{(Triangle)} =\: \dfrac{1}{2} \times 22 \times 13$

$\implies \sf Area_{(Triangle)} =\: \dfrac{1}{2} \times 286$

$\implies \sf Area_{(Triangle)} =\: \dfrac{1 \times 286}{2}$

$\implies \sf Area_{(Triangle)} =\: \dfrac{\cancel{286}}{\cancel{2}}$

$\implies \sf Area_{(Triangle)} =\: \dfrac{143}{1}$

$\implies \sf\bold{\red{Area_{(Triangle)} =\: 143\: cm^2}}$

$\therefore$ The area of a triangle is 143 cm² .

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EXTRA INFORMATION :-

$\clubsuit$ Semi-Perimeter Of Triangle Formula :

$\small \bigstar \: \: \sf\boxed{\bold{\pink{Semi-Perimeter_{(Triangle)} =\: \dfrac{a + b + c}{2}}}}\: \: \: \bigstar$

where,

• a = First Side
• b = Second Side
• c = Third Side

$\clubsuit$ Area Of Triangle by using Heron's formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Triangle)} =\: \sqrt{s(s - a)(s - b)(s - c)}}}}\: \: \: \bigstar$

where,

• s = Semi-Perimeter
• a = First Side
• b = Second Side
• c = Third Side

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