Question

Find the area of a triangle whose perimeter is 22 cm, one side is 9 cm and the difference of the other two sides is 3 cm. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

given one side is a = 9cm

perimeter of a triangle is 2s = 22 cm

= a+b+c = 22

= b+c = 22-9

=b+c = 13

difference between the two sides is 3 cm

=b-c = 3

(1) +(2) = b+ c+b-c = 13 +3 =

2b =16

2 divide by 16

b = 8

therefore √s(s-a) (s - b) (s-c)

2s = 22

2 divide by 22

s= 11

√11×(11-9) ×(11-8)×(11-5)

√11×2×3×6

6√11cm square