Question

find the area of a triangle whose perimeter is 22cm,one side is 9cm and the difference of other two sides is 3cm​

Answer 1

Answer:

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Triangle

Solve for area

A≈13.27cm²

a Side

9

cm

b Base

3

cm

P Perimeter

22

cm

Using the formulas

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣224+4·223·9+4·223·3﹣4·(22·9)2﹣12·222·9·3﹣4·(22·3)2+8·22·92·3+8·22·9·32≈13.2665cm²