Math, asked by jagdeepmahto2, 10 months ago

find the area of a triangle whose side are in the ratio 5 is to 12 is to 3 and its perimeter is 60 CM​

Answers

Answered by Brâiñlynêha
2

\boxed{\bf{\red{Correct\: Question:-}}}

Find the area of a triangle whose side are in the ratio 5 :12:13 and its perimeter is 60 CM

  • If there was 3 in the place of 13 our The triangle is not formed

  • because sum of two sides of triangle is always greater than the third side

\huge\mathbb{SOLUTION:-}

  • The Sides of triangle in ratio .which is

  • 5:12:13

  • And the perimeter=60cm

  • Now first find the side of triangle

\boxed{\sf{Perimeter\:of\: triangle=sum\:of\:all\:sides}}

\bf\underline{\red{According\:To\: Question:-}}

  • Let the side be x

  • so Sides =5x , 12x and 13x

Perimeter=Sum of all sides

5x+12x+13x=60

30x=60

\sf x= \cancel{\frac{60}{30}}=2

  • The value of x is 2

  • so sides of triangle

  • Is = 2× 5=10cm

  • 2×12=24cm

  • 2×13=26cm

We have to find the area of triangle

By heron's formula

\boxed{\sf{ Area=\sqrt{s(s-a)(s-b)(s-c)}}}

where s is the semi perimeter

\sf s=\frac{( a+b+c)}{2}

\sf\leadsto s=\frac{10+26+24}{2}\\ \\ \sf\leadsto s=\cancel{\frac{60}{2}}=30

semi perimeter=30

Now the area of ∆

\sf\implies Area=\sqrt{30(30-10)(30-26)(30-24)}\\ \\ \sf\implies Area=\sqrt{30\times 20\times 4\times 6}\\ \\ \sf\implies Area=\sqrt{10\times 3\times 10\times 2\times 4\times 3\times 2}\\ \\ \sf\implies Area=10\times 3\times 2\times 2\\ \\ \sf\implies Area=120cm{}^{2}

\boxed{\sf{\purple{Area\:of\: triangle=120cm{}^{2}}}}

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