Question

Find the area of a triangle whose sides are 10c.m,8c.m,6cm​

Answer 1

The sides are 10cm, 8cm, 6cm

$s = \frac{10 + 8 + 6}{2} = \cancel\frac{24}{2} = 12$

The area is given as

$\sqrt{s (s- a)(s - b)(s - c)}$

$\sqrt{12(12 - 10)(12 - 8)(12 - 6)}$

$\sqrt{12 \times 2 \times4 \times 6 }$

$\sqrt{576} = 24 \: cm {}^{2}$

Answer 2

Answer:

24cm square is your correct answer