Question

Find the area of a triangle whose sides are 12 cm, 6 cm and 15 cm​

Answer 1

Answer:

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$we \: will \: find \: the \: area \: of \: this \: triangle \: by \: heroine \: formula \\ \\ 1st \: side \: of \: triangle(a) = 12 \: cm \\ \\ 2nd \: side \: of \: triangle(b) = 6 \: cm \\ \\ 3rd \: side \: of \: triangle(c) = 15 \: cm \\ \\ perimeter \: (s) = \frac{a + b + c}{2} \\ \\ perimeter \: (s) = \frac{12 + 6 + 15}{2} = \frac{33}{2} \\ \\ area \: of \: triangle \: abc = \sqrt{s \: (s - a) \: (s - b) \: (s - c)} \\ \\ area \: of \: triangle \: abc = \sqrt{ \frac{33}{2} \: ( \frac{33}{2} - 12)( \frac{33}{2} - 6)( \frac{33}{2} - 15) } \\ \\ area \: of \: triangle \: abc = \sqrt{ \frac{33}{2} ( \frac{33 - 24}{2} )( \frac{33 - 12}{2} )( \frac{33 - 30}{2} )} \\ \\ area \: of \: triangle \: abc = \sqrt{ \frac{33}{2} \times \frac{9}{2} \times \frac{21}{2} \times \frac{3}{2} } \\ \\ area \: of \: triangle \: abc = \sqrt{11 \times \frac{3}{2} \times 3 \times \frac{3}{2} \times 7 \times \frac{3}{2} \times \frac{3}{2} } \\ \\ area \: of \: triangle \: abc = \frac{3}{2} \times \frac{3}{2} \sqrt{11 \times 3 \times 7} \\ \\ area \: of \: triangle \: abc = \frac{9}{4} \sqrt{231} \: \: {cm}^{2} \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$