Question

Find the area of a triangle whose sides are 120cm, 150cm and 200 cm

Answer 1

$\bold{\underline{Hello Here is You're Answer}}$



$\bold{\huge{\underline{ANSWER:-}}}$



$\bold{\fbox{\underline{Define Semi-Perimeter of Triangle}}}$



Let the sides of Semi-Perimeter of Triangle which are Given below;



• a=120 cm


•b=150 cm


•c=200 cm

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$\bold{\underline{Semi-perimeter of Triangle=120+150+200/2=470/2=]235}}$


Semiperimeter of ∆=235cm²


$\bold{\fbox{\underline{ Here, Using heron's Formula}}}$



$\bold{Area \: of \: \: Triangle} \implies \\ \\ \implies \bold{\sqrt{s(s - a)(s - b)(s - c)}} \\ \\ \\ \implies \bold{\sqrt{235(235 - 120)(235- 150)(235- 200)}} \\ \\ \\ \implies \bold{\sqrt{235 \times (115)(85)(35)}} \\ \\ \\ \implies \bold{ \sqrt{8399375}} \\ \\ \\ \huge{ \implies8966.57 {cm}^{2}} \\ \\ \\ \\ \lll \bold{approxmately = 8967 {cm}^{2}} \lll$



$\bold{\underline{CONCLUSION:- Area of Triangle = 8967{cm}^{3} }}$

Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

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$\bold{\huge{\underline{\underline{\rm{ Given :}}}}}$

Sides -

a = 200 cm

a = 200 cm b = 150 cm

c = 120 cm

$\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}$

Area of Triangle .

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$area(a) = \sqrt{p(p - a)(p - b)(p - c)}$

Where P is half perimeter.

$p = \frac{a + b + c}{2}$

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$\purple{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

First find out the value of P.

$p = \frac{200+150+120}{2} \\ p = \frac{470}{2}$

$p = 235$

Now Area is ,

$a = \sqrt{235(235 - 200)(235- 150)(235 - 120)} \\ a = \sqrt{235 \times 35 \times 85 \times 115}$

$a = \sqrt{80,399,375}$

$\boxed{a = 8,966.56986}$

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