Math, asked by bhanupriyaparihar020, 1 month ago

Find the area of a triangle whose sides are 20cm,21cm, and 13cm.Find the length of the altitude corresponding to the longest side.​

Answers

Answered by itzstylishbandi
0

Given, sides of triangle 5 cm, 12 cm, 13 cm.

Now semi perimeter,

 

s =  \frac{a + b + c}{2}

s =  \frac{20 + 12 + 13}{2}

s = 22.5

Using heron's formula,

Area of triangle

√s(s−a)(s−b)(s−c)

=√22.5(22.5−5)(22.5−12)(22.5−13)

=√22.5×17.5×10.5×9.5

Using altitude,

area of triangle =21× base × altitude 

 = 39276.5625cm ^{2}

=21×13× altitude

 =30

= altitude =1330×2

=4.61 cm

So, altitude corresponding to largest side is 4.61 cm.

Similar questions