Question

find the area of a triangle whose sides are 40m 24m and 32m.

Answer 1

Area of triangle=root p(p-a)(p-b)(p-c)
p=perimeter of the triangle=a+b+c/2
here,a=40,b=24,c=32
p=40+24+32/2=96/2=48
then area of triangle= root 48(48-40)(48-24)(40-32)=root 147456 = 384 
ANS-384 

Answer 2

Answer:

384 square m.

Step-by-step explanation:

Sides of triangle :

a = 40 m

b =24 m

c =32 m

To calculate the area of given triangle we will use the heron's formula :

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

a,b,c are the side lengths of triangle  

Now substitute the values :

$s = \frac{40+24+32}{2}$

$s =48$

$Area = \sqrt{48(48-40)(48-24)(48-32)}$

$Area = 384$

Hence the area of the triangle is 384 square m.