Question

Find the area of a triangle whose sides are 41 cm, 15cm, and 28 cm.
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Answer 1

s=41+15+28/2

s=84/2=42

area=√s(s-a)(s-b)(s-c)

area=√42(42-41)(42-15)(42-28)

area=√42×1×17×14

Area=14√51

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