Question

Find the area of a triangle whose sides are 48cm, 14cm and 50cm​

Answer 1

Answer:

336 is correct answer.

Answer 2

Given

we have given sides of Triangle are 48cm,14cm & 50cm

To find

We have to find area of triangle.

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

let the sides be a ,b & c respectively.

a= 48cm, b= 14cm & c= 50cm

First we find S ( perimeter )

S= a+b+c /2

S= 48+14+50/2

S=112/2

S=56

Area of triangle= √S(S-a)(S-b)(S-c)

Area of triangle=√56(56-48)(56-14)(56-50)

Area of triangle=√56×8×42×6

Area of triangle=√2×2×2×7×2×2×2×2×3×7×2×3

Area of triangle= 2×2×2×2×7×3

Area of triangle= 16× 21

Area of triangle=336cm²

Extra information=>

Above triangle is a scalene triangle [all sides are different].

If Normal triangle is given then we use area of triangle= 1/2×base×height.