Question

Find the area of a triangle whose sides are :
(a) a = 8 cm, b = 11 cm, c = 13 cm
you have to use Hero's formula for Area of a Triangle ​

Answer 1

Answer:

43.82

Step-by-step explanation:

A=√s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c/2

Solving forA

A=1/4

√-a⁴+2(ab)²+2(ac)²﹣b⁴+2(bc)²﹣c⁴

=1/4

√-8⁴+2·(8·11)²+2·(8·13)²﹣11⁴+2·(11·13)²﹣13⁴

=43.8178

Answer 2

Answer:

8√30 sq cm

Step-by-step explanation:

s=a+b+c/2

=8+11+13/2

=32/2

=16

area of triangle=√s(s-a)(s-b)(s-c)

=√16(16-8)(16-11)(16-13)

=√16×8×5×3

=√8×2×8×5×3

=8√30

hence, the are of triangle is 8√30 sq cm