Question

Find the area of a triangle, whose sides are along the lines x = -5, y = 0, and 3x + 5y = 20

Answer 1

Step-by-step explanation:

1. x=-5
2. y=0
3. 3x+5y=20

when x=-5

3(-5)+5y=20

-15+5y=20

5y=35÷5

y=7

A= (-5,7)

when y is equal to 0

3x +5(0) =20

3x=20

x=20÷3

x=6.6

B=(6.6,0)

then C= (-5,0) given

Base =11.6cm

height =7cm

area of ABC

=1÷2*Base*height

=1÷2* 11.6*7

=1÷2*81.2

=40.6 cm square units