find the area of a triangle whose sides are along the lines x = 3, Y = 0 and 4 x + 5 Y = 20
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x = 3…………(1)
y=0…………..(2)
4x+5y=20……..(3)
by solving eqn. (1)&(2). x=3, y=0. or. A(3,0)
by solving eqn. (2) &(3) y=0 , x=5. or. B(5,0)
by solving eqn. (3) &(1) x=3 , y=8/5. Or. C(3,8/5)
Area of the triangle ABC=1/2.[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
=1/2.[3(0–8/5)+5(8/5–0)+3(0–0)]
=1/2.[-24/5+8]
=1/2.(16/5)
=8/5 = 1.6 sq.unit. Answer
Step-by-step explanation:
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